0.00/0.00 MAYBE 0.00/0.00 0.00/0.00 0.00/0.00 Succeeded in reading "/export/starexec/sandbox2/benchmark/theBenchmark.trs". 0.00/0.00 (CONDITIONTYPE ORIENTED) 0.00/0.00 (VAR x) 0.00/0.00 (RULES 0.00/0.00 c -> k(f(a)) 0.00/0.00 c -> k(g(b)) 0.00/0.00 h(x) -> k(x) 0.00/0.00 h(f(a)) -> c 0.00/0.00 a -> b 0.00/0.00 f(x) -> g(x) | h(f(x)) == k(g(b)) 0.00/0.00 ) 0.00/0.00 (COMMENT doi:10.1007/3-540-19242-5_3 [49] Example B as join CTRS; correction of Cops #273 submitted by: Thomas Sternagel) 0.00/0.00 0.00/0.00 No "->="-rules. 0.00/0.00 0.00/0.00 Decomposed conditions if possible. 0.00/0.00 (CONDITIONTYPE ORIENTED) 0.00/0.00 (VAR x) 0.00/0.00 (RULES 0.00/0.00 c -> k(f(a)) 0.00/0.00 c -> k(g(b)) 0.00/0.00 h(x) -> k(x) 0.00/0.00 h(f(a)) -> c 0.00/0.00 a -> b 0.00/0.00 f(x) -> g(x) | h(f(x)) == k(g(b)) 0.00/0.00 ) 0.00/0.00 (COMMENT doi:10.1007/3-540-19242-5_3 [49] Example B as join CTRS; correction of Cops #273 submitted by: Thomas Sternagel) 0.00/0.00 0.00/0.00 Removed infeasible rules as much as possible. 0.00/0.00 (CONDITIONTYPE ORIENTED) 0.00/0.00 (VAR x) 0.00/0.00 (RULES 0.00/0.00 c -> k(f(a)) 0.00/0.00 c -> k(g(b)) 0.00/0.00 h(x) -> k(x) 0.00/0.00 h(f(a)) -> c 0.00/0.00 a -> b 0.00/0.00 f(x) -> g(x) | h(f(x)) == k(g(b)) 0.00/0.00 ) 0.00/0.00 (COMMENT doi:10.1007/3-540-19242-5_3 [49] Example B as join CTRS; correction of Cops #273 submitted by: Thomas Sternagel) 0.00/0.00 0.00/0.00 Try to disprove confluence of the following (C)TRS: 0.00/0.00 (CONDITIONTYPE ORIENTED) 0.00/0.00 (VAR x) 0.00/0.00 (RULES 0.00/0.00 c -> k(f(a)) 0.00/0.00 c -> k(g(b)) 0.00/0.00 h(x) -> k(x) 0.00/0.00 h(f(a)) -> c 0.00/0.00 a -> b 0.00/0.00 f(x) -> g(x) | h(f(x)) == k(g(b)) 0.00/0.00 ) 0.00/0.00 (COMMENT doi:10.1007/3-540-19242-5_3 [49] Example B as join CTRS; correction of Cops #273 submitted by: Thomas Sternagel) 0.00/0.00 0.00/0.00 Failed either to apply SR and U for normal 1CTRSs to the above CTRS or to prove confluence of any converted TRSs. 0.00/0.00 0.00/0.00 Try to apply SR and U for 3DCTRSs to the above CTRS. 0.00/0.00 0.00/0.00 Succeeded in applying U for 3DCTRSs to the above CTRS. 0.00/0.00 U(R) = 0.00/0.00 (VAR x1) 0.00/0.00 (RULES 0.00/0.00 c -> k(f(a)) 0.00/0.00 c -> k(g(b)) 0.00/0.00 h(x1) -> k(x1) 0.00/0.00 h(f(a)) -> c 0.00/0.00 a -> b 0.00/0.00 f(x1) -> u1(h(f(x1)),x1) 0.00/0.00 u1(k(g(b)),x1) -> g(x1) 0.00/0.00 ) 0.00/0.00 0.00/0.00 U for 3DCTRSs is sound for the above CTRS. 0.00/0.00 0.00/0.00 Failed to prove confluence of U(R). 0.00/0.00 0.00/0.00 Try to prove operational termination of R, i.e., termination of U(R). 0.00/0.00 0.00/0.00 Failed to prove operational termination of R. 0.00/0.00 0.00/0.00 MAYBE 0.00/0.00 EOF