0.00/0.00	MAYBE
0.00/0.00	
0.00/0.00	
0.00/0.00	Succeeded in reading "/export/starexec/sandbox2/benchmark/theBenchmark.trs".
0.00/0.00	    (CONDITIONTYPE ORIENTED)
0.00/0.00	    (VAR z2 z1 rest y x)
0.00/0.00	    (RULES
0.00/0.00	      cons(x,cons(y,rest)) -> cons(z1,cons(z2,rest)) | orient(x,y) == pair(z1,z2)
0.00/0.00	      cons(x,cons(x,rest)) -> cons(x,rest)
0.00/0.00	      orient(s(x),s(y)) -> pair(s(z1),s(z2)) | orient(x,y) == pair(z1,z2)
0.00/0.00	      orient(s(x),0) -> pair(0,s(x))
0.00/0.00	    )
0.00/0.00	    (COMMENT [75] Example 36 submitted by: Thomas Sternagel and Aart Middeldorp)
0.00/0.00	
0.00/0.00	No "->="-rules.
0.00/0.00	
0.00/0.00	Decomposed conditions if possible.
0.00/0.00	    (CONDITIONTYPE ORIENTED)
0.00/0.00	    (VAR z2 z1 rest y x)
0.00/0.00	    (RULES
0.00/0.00	      cons(x,cons(y,rest)) -> cons(z1,cons(z2,rest)) | orient(x,y) == pair(z1,z2)
0.00/0.00	      cons(x,cons(x,rest)) -> cons(x,rest)
0.00/0.00	      orient(s(x),s(y)) -> pair(s(z1),s(z2)) | orient(x,y) == pair(z1,z2)
0.00/0.00	      orient(s(x),0) -> pair(0,s(x))
0.00/0.00	    )
0.00/0.00	    (COMMENT [75] Example 36 submitted by: Thomas Sternagel and Aart Middeldorp)
0.00/0.00	
0.00/0.00	Removed infeasible rules as much as possible.
0.00/0.00	    (CONDITIONTYPE ORIENTED)
0.00/0.00	    (VAR z2 z1 rest y x)
0.00/0.00	    (RULES
0.00/0.00	      cons(x,cons(y,rest)) -> cons(z1,cons(z2,rest)) | orient(x,y) == pair(z1,z2)
0.00/0.00	      cons(x,cons(x,rest)) -> cons(x,rest)
0.00/0.00	      orient(s(x),s(y)) -> pair(s(z1),s(z2)) | orient(x,y) == pair(z1,z2)
0.00/0.00	      orient(s(x),0) -> pair(0,s(x))
0.00/0.00	    )
0.00/0.00	    (COMMENT [75] Example 36 submitted by: Thomas Sternagel and Aart Middeldorp)
0.00/0.00	
0.00/0.00	Try to disprove confluence of the following (C)TRS:
0.00/0.00	    (CONDITIONTYPE ORIENTED)
0.00/0.00	    (VAR z2 z1 rest y x)
0.00/0.00	    (RULES
0.00/0.00	      cons(x,cons(y,rest)) -> cons(z1,cons(z2,rest)) | orient(x,y) == pair(z1,z2)
0.00/0.00	      cons(x,cons(x,rest)) -> cons(x,rest)
0.00/0.00	      orient(s(x),s(y)) -> pair(s(z1),s(z2)) | orient(x,y) == pair(z1,z2)
0.00/0.00	      orient(s(x),0) -> pair(0,s(x))
0.00/0.00	    )
0.00/0.00	    (COMMENT [75] Example 36 submitted by: Thomas Sternagel and Aart Middeldorp)
0.00/0.00	
0.00/0.00	Failed either to apply SR and U for normal 1CTRSs to the above CTRS or to prove confluence of any converted TRSs.
0.00/0.00	
0.00/0.00	Try to apply SR and U for 3DCTRSs to the above CTRS.
0.00/0.00	
0.00/0.00	Succeeded in applying U for 3DCTRSs to the above CTRS.
0.00/0.00	U(R) =
0.00/0.00	    (VAR x2 x1 x3 x5 x4)
0.00/0.00	    (RULES
0.00/0.00	      cons(x1,cons(x1,x2)) -> cons(x1,x2)
0.00/0.00	      cons(x1,cons(x2,x3)) -> u1(orient(x1,x2),x1,x2,x3)
0.00/0.00	      u1(pair(x4,x5),x1,x2,x3) -> cons(x4,cons(x5,x3))
0.00/0.00	      orient(s(x1),0) -> pair(0,s(x1))
0.00/0.00	      orient(s(x1),s(x2)) -> u2(orient(x1,x2),x1,x2)
0.00/0.00	      u2(pair(x3,x4),x1,x2) -> pair(s(x3),s(x4))
0.00/0.00	    )
0.00/0.00	
0.00/0.00	Failed to prove confluence of U(R).
0.00/0.00	
0.00/0.00	Try to prove operational termination of R, i.e., termination of U(R).
0.00/0.00	
0.00/0.00	Failed to prove operational termination of R.
0.00/0.00	
0.00/0.00	MAYBE
0.00/0.00	EOF