0.00/0.00 MAYBE 0.00/0.00 0.00/0.00 0.00/0.00 Succeeded in reading "/export/starexec/sandbox/benchmark/theBenchmark.trs". 0.00/0.00 (CONDITIONTYPE ORIENTED) 0.00/0.00 (VAR y x z z\') 0.00/0.00 (RULES 0.00/0.00 plus(0,y) -> y 0.00/0.00 plus(s(x),y) -> plus(x,s(y)) 0.00/0.00 f(x,y) -> z | plus(x,y) == plus(z,z\') 0.00/0.00 ) 0.00/0.00 (COMMENT doi:10.1007/3-540-58216-9_40 [45] Example 4.1.a submitted by: Thomas Sternagel and Aart Middeldorp) 0.00/0.00 0.00/0.00 No "->="-rules. 0.00/0.00 0.00/0.00 Decomposed conditions if possible. 0.00/0.00 (CONDITIONTYPE ORIENTED) 0.00/0.00 (VAR y x z z\') 0.00/0.00 (RULES 0.00/0.00 plus(0,y) -> y 0.00/0.00 plus(s(x),y) -> plus(x,s(y)) 0.00/0.00 f(x,y) -> z | plus(x,y) == plus(z,z\') 0.00/0.00 ) 0.00/0.00 (COMMENT doi:10.1007/3-540-58216-9_40 [45] Example 4.1.a submitted by: Thomas Sternagel and Aart Middeldorp) 0.00/0.00 0.00/0.00 Removed infeasible rules as much as possible. 0.00/0.00 (CONDITIONTYPE ORIENTED) 0.00/0.00 (VAR y x z z\') 0.00/0.00 (RULES 0.00/0.00 plus(0,y) -> y 0.00/0.00 plus(s(x),y) -> plus(x,s(y)) 0.00/0.00 f(x,y) -> z | plus(x,y) == plus(z,z\') 0.00/0.00 ) 0.00/0.00 (COMMENT doi:10.1007/3-540-58216-9_40 [45] Example 4.1.a submitted by: Thomas Sternagel and Aart Middeldorp) 0.00/0.00 0.00/0.00 Try to disprove confluence of the following (C)TRS: 0.00/0.00 (CONDITIONTYPE ORIENTED) 0.00/0.00 (VAR y x z z\') 0.00/0.00 (RULES 0.00/0.00 plus(0,y) -> y 0.00/0.00 plus(s(x),y) -> plus(x,s(y)) 0.00/0.00 f(x,y) -> z | plus(x,y) == plus(z,z\') 0.00/0.00 ) 0.00/0.00 (COMMENT doi:10.1007/3-540-58216-9_40 [45] Example 4.1.a submitted by: Thomas Sternagel and Aart Middeldorp) 0.00/0.00 0.00/0.00 Failed either to apply SR and U for normal 1CTRSs to the above CTRS or to prove confluence of any converted TRSs. 0.00/0.00 0.00/0.00 Try to apply SR and U for 3DCTRSs to the above CTRS. 0.00/0.00 0.00/0.00 Succeeded in applying U for 3DCTRSs to the above CTRS. 0.00/0.00 U(R) = 0.00/0.00 (VAR x1 x2 x4 x3) 0.00/0.00 (RULES 0.00/0.00 plus(0,x1) -> x1 0.00/0.00 plus(s(x1),x2) -> plus(x1,s(x2)) 0.00/0.00 f(x1,x2) -> u1(plus(x1,x2),x1,x2) 0.00/0.00 u1(plus(x3,x4),x1,x2) -> x3 0.00/0.00 ) 0.00/0.00 0.00/0.00 U for 3DCTRSs is sound for the above CTRS. 0.00/0.00 0.00/0.00 Failed to prove confluence of U(R). 0.00/0.00 0.00/0.00 Try to prove operational termination of R, i.e., termination of U(R). 0.00/0.00 0.00/0.00 Succeeded in proving operational termination of R. 0.00/0.00 0.00/0.00 Try to prove joinability of all (conditional) CPs. 0.00/0.00 0.00/0.00 Failed to prove termination of U(R). 0.00/0.00 0.00/0.00 MAYBE 0.00/0.00 EOF