0.00/0.02	NO
0.00/0.02	(ignored inputs)COMMENT [75] Example 41 submitted by: Thomas Sternagel and Aart Middeldorp
0.00/0.02	Conditional Rewrite Rules:
0.00/0.02	   [ s(a) -> c,
0.00/0.02	     s(b) -> c,
0.00/0.02	     c -> t(k),
0.00/0.02	     c -> t(l),
0.00/0.02	     f(?x) -> ?z | s(?x) == ?z,
0.00/0.02	     g(?x,?x) -> h(?x,?x) ]
0.00/0.02	Check whether all rules are type 3
0.00/0.02	OK
0.00/0.02	Check whether the input is deterministic
0.00/0.02	OK
0.00/0.02	Result of unraveling:
0.00/0.02	   [ s(a) -> c,
0.00/0.02	     s(b) -> c,
0.00/0.02	     c -> t(k),
0.00/0.02	     c -> t(l),
0.00/0.02	     f(?x) -> U0(s(?x),?x),
0.00/0.02	     U0(?z,?x) -> ?z,
0.00/0.02	     g(?x,?x) -> h(?x,?x) ]
0.00/0.02	Check whether U(R) is terminating
0.00/0.02	OK
0.00/0.02	Check whether the input is weakly left-linear
0.00/0.02	not weakly left-linear
0.00/0.02	Check whether U(R) is confluent
0.00/0.02	U(R) is not confluent
0.00/0.02	Conditional critical pairs (CCPs):
0.00/0.02	   [ t(l) = t(k),
0.00/0.02	     t(k) = t(l) ]
0.00/0.02	Check whether the input is almost orthogonale
0.00/0.02	not almost orthogonal
0.00/0.02	not weakly left-linear
0.00/0.02	Check whether the input is absolutely irreducible
0.00/0.02	OK
0.00/0.02	Check whether all CCPs are joinable
0.00/0.02	Some ccp may be feasible but not joinable
0.00/0.02	   [ t(l) = t(k),
0.00/0.02	     t(k) = t(l) ]
0.00/0.02	A feasible but not joinable CCP: t(l) = t(k)
0.00/0.02	/export/starexec/sandbox2/benchmark/theBenchmark.trs: Success(not CR)
0.00/0.02	(0 msec.)
0.00/0.02	EOF