0.00/0.09	MAYBE
0.00/0.09	(ignored inputs)COMMENT doi:10.1016/j.jlap.2009.08.001 [73] Example 17 submitted by: Thomas Sternagel and Aart Middeldorp
0.00/0.09	Conditional Rewrite Rules:
0.00/0.09	   [ f(?x) -> ?y | a == h(?y),
0.00/0.09	     g(?x,b) -> g(f(c),?x) | f(b) == ?x,?x == c,
0.00/0.09	     a -> h(b),
0.00/0.09	     a -> h(c) ]
0.00/0.09	Check whether all rules are type 3
0.00/0.09	OK
0.00/0.09	Check whether the input is deterministic
0.00/0.09	OK
0.00/0.09	Result of unraveling:
0.00/0.09	   [ f(?x) -> U0(a,?x),
0.00/0.09	     U0(h(?y),?x) -> ?y,
0.00/0.09	     g(?x,b) -> U1(f(b),?x),
0.00/0.09	     U1(?x,?x) -> U2(?x,?x),
0.00/0.09	     U2(c,?x) -> g(f(c),?x),
0.00/0.09	     a -> h(b),
0.00/0.09	     a -> h(c) ]
0.00/0.09	Check whether U(R) is terminating
0.00/0.09	failed to show termination
0.00/0.09	Check whether the input is weakly left-linear
0.00/0.09	not weakly left-linear
0.00/0.09	Conditional critical pairs (CCPs):
0.00/0.09	   [ h(c) = h(b),
0.00/0.09	     h(b) = h(c) ]
0.00/0.09	Check whether the input is almost orthogonale
0.00/0.09	not almost orthogonal
0.00/0.09	not weakly left-linear
0.00/0.09	/export/starexec/sandbox2/benchmark/theBenchmark.trs: Failure(unknown CR)
0.00/0.09	(43 msec.)
0.00/0.09	EOF