0.00/0.02	NO
0.00/0.02	(ignored inputs)COMMENT [75] Example 29 submitted by: Thomas Sternagel and Aart Middeldorp
0.00/0.02	Conditional Rewrite Rules:
0.00/0.02	   [ a -> t(c),
0.00/0.02	     a -> t(d),
0.00/0.02	     f(?x,?y) -> ?z | ?x == t(?z),
0.00/0.02	     g(?x,?x) -> h(?x,?x) ]
0.00/0.02	Check whether all rules are type 3
0.00/0.02	OK
0.00/0.02	Check whether the input is deterministic
0.00/0.02	OK
0.00/0.02	Result of unraveling:
0.00/0.02	   [ a -> t(c),
0.00/0.02	     a -> t(d),
0.00/0.02	     f(?x,?y) -> U0(?x,?x,?y),
0.00/0.02	     U0(t(?z),?x,?y) -> ?z,
0.00/0.02	     g(?x,?x) -> h(?x,?x) ]
0.00/0.02	Check whether U(R) is terminating
0.00/0.02	OK
0.00/0.02	Check whether the input is weakly left-linear
0.00/0.02	not weakly left-linear
0.00/0.02	Check whether U(R) is confluent
0.00/0.02	U(R) is not confluent
0.00/0.02	Conditional critical pairs (CCPs):
0.00/0.02	   [ t(d) = t(c),
0.00/0.02	     t(c) = t(d) ]
0.00/0.02	Check whether the input is almost orthogonale
0.00/0.02	not almost orthogonal
0.00/0.02	not weakly left-linear
0.00/0.02	Check whether the input is absolutely irreducible
0.00/0.02	OK
0.00/0.02	Check whether all CCPs are joinable
0.00/0.02	Some ccp may be feasible but not joinable
0.00/0.02	   [ t(d) = t(c),
0.00/0.02	     t(c) = t(d) ]
0.00/0.02	A feasible but not joinable CCP: t(d) = t(c)
0.00/0.02	/export/starexec/sandbox/benchmark/theBenchmark.trs: Success(not CR)
0.00/0.02	(0 msec.)
0.00/0.02	EOF