0.00/0.02	YES
0.00/0.02	(ignored inputs)COMMENT doi:10.2168/LMCS-8 ( 3:4 ) 2012 [64] Example 4.11 ( R_10 ) submitted by: Thomas Sternagel and Aart Middeldorp
0.00/0.02	Conditional Rewrite Rules:
0.00/0.02	   [ f(?x) -> e | d == l,
0.00/0.02	     h(?x,?x) -> A ]
0.00/0.02	Check whether all rules are type 3
0.00/0.02	OK
0.00/0.02	Check whether the input is deterministic
0.00/0.02	OK
0.00/0.02	Result of unraveling:
0.00/0.02	   [ f(?x) -> U0(d,?x),
0.00/0.02	     U0(l,?x) -> e,
0.00/0.02	     h(?x,?x) -> A ]
0.00/0.02	Check whether U(R) is terminating
0.00/0.02	OK
0.00/0.02	Check whether the input is weakly left-linear
0.00/0.02	OK
0.00/0.02	Check whether U(R) is confluent
0.00/0.02	OK
0.00/0.02	R is deterministic, weakly left-linear and U(R) is confluent
0.00/0.02	/export/starexec/sandbox2/benchmark/theBenchmark.trs: Success(CR)
0.00/0.02	(0 msec.)
0.00/0.02	EOF